y^2-13y+26=0

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Solution for y^2-13y+26=0 equation: 



y^2-13y+26=0

a = 1; b = -13; c = +26;
Δ = b2-4ac
Δ = -132-4·1·26
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{65}}{2*1}=\frac{13-\sqrt{65}}{2}
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{65}}{2*1}=\frac{13+\sqrt{65}}{2}
$

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